Find all the natural number (x,y) which meets following condition;
$1^2 + 2^2 + \hdots + x^2 = y^2$
You may find the trivial solution (x,y) = (1,1).
Can you prove that there are infinitely many solutions? Or if it doesn't, can you show all the possible solutions?
The Answer Will Be Posted Next Week, Sep 6, 2009.
*Hint : (mod 6)
Sunday, August 30, 2009
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